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1^2 + 4^2 + 7^2 + ... + (3n - 2)^2 = quantity n times quantity six n squared...
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Mathematics, 12.02.2020 04:18 taee67
If you can
1^2 + 4^2 + 7^2 + ... + (3n - 2)^2 = quantity n times quantity six n squared minus three n minus one all divided by two
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