The manager of a theater noted that for every 10 admission tickets sold, the theater sells 3 bags of popcorn at $2.25 each, 4 sodas at $1.50 each, and 2 candy bars at $1.00 each. To the nearest cent, what is the average (arithmetic mean) amount of these snack sales per ticket sold?

$1.475 is the average amount of snack sales per ticket sold.

Step-by-step explanation:

We are given the following in the question:

Number of popcorn bags sold = 3

Cost of  a popcorn bag = $2.25

Total cost of popcorn bag = = $6.75

Number of soda sold = 4

Cost of  a soda = $1.50

Total cost of soda = = $6.00

Number of candy bars sold = 2

Cost of  a candy bar = $1.00

Total cost of candy bars =   = $2.00

Total sales =

Total cost of popcorn + Total cost of soda + Total cost of candy bar

Average amount of snack sales per ticket sold =

Thus, $1.475 is the average amount of snack sales per ticket sold.

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.