My Scando-Germanic friend, Odd Zahlen, often brings a die to class to answer multiple-choice final exam questions. Each multiple-choice question on this particular examination consists of three choices, and Odd decides to pick answer (a) if a 1 or 2 appears on a roll of the die, to pick (b) if a 3 or 4 appears on the die, or to pick (c) if a 5 or 6 appears. Assume that the correct answers are uniformly distributed among the choices (a), (b), and (c). What is the probability of obtaining exactly 5 correct answers on a ten question examination using this method?

Step-by-step explanation:

From each multiple-choice question, there consists three answers to each;

So the probability of picking, the correct answer as they are uniformly distributed among the choices (a), (b), and (c) will be;

P(correct answer) =

Now, to determine the probability of obtaining exactly 5 correct answers on a ten question examination using this method

Let use A as representative for the numbers of correct answers out of 10 questions that is being answered.

∴

the answer is a

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)