Given △ABC with vertices: A(−1, 7), B(−4, 2), C(−3, 1). Reflect △ABC across the line y = −2 to create image △A'B'C'. Reflect △A'B'C' across the line x = 2 to create image △A″B″C″. What are the coordinates of the vertices of △A″B″C″? What single transformation would take △ABC onto △A″B″C″?

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

too hard the other guy did it

step-by-step explanation: