Streaklines are traced out by neutrally buoyant marker fluid injected into a flow field from a fixed point in space. A particle of the marker fluid that is at point ðx, yÞ at time t must have passed through the injection point ðx0,y0Þ at some earlier instant t =τ. The time history of a marker particle may be found by solving the pathline equations for the initial conditions that x=x0, y=y0 when t =τ. The present locations of particles on the streakline are obtained by setting τ equal to values in the range 0≤τ ≤t. Consider the flow field V! =axð1+btÞ^i+cy^j, where a=c=1 s−1 and b=0:2 s−1. Coordinates are measured in meters. Plot the streakline that passes through the initial point ðx0,y0Þ=ð1,1Þ, during the interval from t =0 to t =3 s. Compare with the streamline plotted through the same point at the instants t =0, 1, and 2 s.

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

from the sentence, "tomorrow morning, akiko will arrive an hour late" depicts a third person perspective because it doesn't use any pronoun to replace akiko, the subject of the sentence, and it is in singular form since akiko is only one person.