What is the value of x in the equation 2(x-3)+9=3(x+1)+x ?
a. x = -3
b. x = -1
c. x = 0
d. x = 3

c. x = 0

Step-by-step explanation:

2(x-3)+9=3(x+1)+x

⇔

2x - 6 + 9 = 3x + 3 + x

⇔

2x + 3 = 4x + 3

⇔

2x = 4x

⇔

4x - 2x = 0

⇔

2x = 0

⇔

x = 0

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

d.) yes, because the volume of the cone is greater than the volume of the sphere

step-by-step explanation: