The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6,008 kilograms per square centimeter and a standard deviation of 91 kilograms per square centimeter. Determine the probability a sample's strength is exactly 6,032 kilograms per centimeter squared. Round your answer to two decimal places.

0.60

Step-by-step explanation:

Mean m = 6008 kgcm-²

Standard deviation d = 91 kgcm-²

x = 6032 kgcm-²

P(z= 6032) = ¢(Z) = ¢( x-m/d)

P(z = 6032) = ¢ (6032-6008/91)

P(z = 6032)= ¢(0.264)

P(z= 6032) = 0.6026 = 0.60

Therefore, the probability a sample's strength is exactly 6,032 kilograms per centimeter squared is 0.60

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

the answer is 13 cm