Does there exist a Pythagorean triple of the form m, m+7, and m+8, where m is a natural number? If the answer is yes, determine all such Pythagorean triples. If the answer is no, prove that no such Pythagorean triple exists.

Yes, m = 5

Step-by-step explanation:

m^2 + (m+7)^2 = (m+8)^2 by Pythagorean Theorem. You get m = 5, -3 so m = 5 since -3 is not a natural number.

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the answer to this question is 3/19

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