Lbinism, lack of pigmentation in humans, results from an autosomal recessive gene. Two parents with normal pigmentation have an albino child. What is the probability that their next child will be wild type?

Step-by-step explanation:

When two parents are normal but they have albino child.

It means both parents are Heterozygous for this gene. The genotype of parents are Aa

Parents: Aa × Aa

Punnet square:

GametesAa

AAA ( normal)Aa(normal)

aAa(normal)aa( albino)

Now the probability of albino child is not he included because the children is already produced. That's why the probability of normal child is 3/4

But according to your mastering that answer is not correct

It means there is included of both children in calculation of probability = (1/4) ×(3/4) =3/16

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

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step-by-step explanation: