The area of a square is 49 square inches. Find the number of inches in the length of a diagonal. Express your answer in simplest radical form.

9.9 inches

Step-by-step explanation:

if the area of the square is 49 we have and know that the base and height are equal we can express it as follows

X is one side of the square.

X * X = 49

X^2 = 49

X = √49

X = 7

by Pythagoras we can calculate the diagonal of the triangle formed by 2 sides of the square with the following expression

Y is the diagonal

7^2 + 7^2 = Y^2

49 + 49 = Y^2

√98 = Y

Y = 9.9

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

a and c

step-by-step explanation: