Describe the right-hand and the left-hand behavior of the graph of q(x)=6x5+8x3+26
.
Select one:
a. Because the degree is odd and the leading coefficient is positive, the graph rises to the left and falls to the right.
b. Because the degree is odd and the leading coefficient is positive, the graph falls to the left and falls to the right.
c. Because the degree is even and the leading coefficient is positive, the graph rises to the left and rises to the right.
d. Because the degree is odd and the leading coefficient is positive, the graph falls to the left and rises to the right.
e. Because the degree is odd and the leading coefficient is positive, the graph rises to the left and rises to the right.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function