Biologists stocked a lake with 500 fish and estimated the environmental carrying capacity to be 6100. The number of fish doubled in the first year. Assume that the size of the fish population satisfies the logistic equation dPdt=kP(1−PK), where t is measured in years. Find an expression for the size of the population. Hint: Use partial fraction decomposition to solve for P. k= P= $$ How long will it take for the population to increase to 3050 (half of the carrying capacity)? It will take $$ years.

Step-by-step explanation:

The size of fish population satisfies the logistic equation:

K=6100 is the carry capacity. Substitute to get:

We separate variables to obtain:

Use partial fraction decomposition to get:

Integrate to obtain:

We apply the ICs to get,

The expression for population size is

b)

Substitute P=3050 into  

This implies that:

Solve for t to get:

$320 to $405

step by step explanation:

in one day he earns between $64 and $81

therefore if he works for 5 days, he will earn between 64 x 5 to 81 x 5

= $320 to $405

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.