1.
An object 2.0-cm tall is located 10.0-cm in front of a converging lens
with a focal length of 5.0-cm. Find the location and height of the
image. Locate lens toward the center of your paper.

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

=3

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

m = 12/20 = 0.6

size of final image = .6 x 30 = 18 cm

21.4 i did it already for s1

step-by-step explanation: