Given P(A) = 0.3 and P(B) = 0.5, do the following. (a) If A and B are mutually exclusive events, compute P(A or B). (b) If P(A and B) = 0.1, compute P(A or B).

a) P(A or B) = 0.8

b) P(A or B) = 0.7

Step-by-step explanation:

We have two events:

Event A

Event B

We have that:

In which P(a) is the probability that only a happens and is the probability that both A and B happen.

By the same logic, we have that:

P(A or B) is

We have that:

(a) If A and B are mutually exclusive events, compute P(A or B).

Since A and B are mutually exclusive events, we have that:

So

----------------

Or operation:

(b) If P(A and B) = 0.1, compute P(A or B).

So

----------------

Or operation:

hkhkhkhkhkhkhk

step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0