Recently, a random sample of 25–34 year olds was asked, "How much do you currently have in savings, not including retirement savings?" The following data represent the responses to the survey. Approximate the mean and standard deviation amount of savings.

You forgot to put the data

Step-by-step explanation:

Because we  don't have the data that represent the responses to the survery I can show you how to can get the mean and the standard deviation.

The mean is the average of the numbers. We use it to get a representative value of the data we are manipulating.  We calculate it by adding all the numbers and then divide the sum by how many numbers we have.

The formule we use is:

∑

The standard deviation is a measure of the variation or dispersion of the data we have. A low deviation indicates that our data is few disperced, on the other hand a big deviation indicates a high dispersion of the data.

The formule we use is:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph