Dale has three dollars more than twice the amount of money that Leo has.

Which statement makes this comparison using the correct variable expression?

If Leo has d dollars, then Dale has d2+3 dollars.
If Leo has d dollars, then Dale has 2d + 3 ⁢ dollars.
If Leo has d dollars, then Dale has 2(3)+d ⁢ dollars.
If Leo has d dollars, then Dale has d + 2 + 3 ⁢ dollars.

If Leo has d dollars, then Dale has 2d + 3

Step-by-step explanation:

If we say Leo has x amount of money. Now we say that Dale has $3 more (x + 3) then twice the amount of money Dale has. Twice the amount of money Dale has is equal to 2x. And so by having three more dollars than this amount would be equal to 2x + 3 or in this case 2d + 3. It may be more helpful to read the question and attempt it on your own before reading the options bc they may confuse you.

Hope this helps!

B)If Leo has d dollars, then Dale has 2d + 3 ⁢ dollars.

Step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places