A mother invests $2000 in a bank account at the time of her daughter's birth. The interest is compounded quarterly at a rate of 8%. What will be the value of the daughter's account on her twentieth birthday, assuming no other deposits or withdrawals are made during this period?

3696508354.42 $

Step-by-step explanation:

P= 2000$

No of terms per year = 4

==> number of terms for the period= 4×20=80

Quarterly interest rate = 8

so yearly rate =  8/3×12=48%

We know formula for compound interest is;

A= P

Where,

A= amount required

P = principal or invested amount

R = rate of interest per year

T = number of terms for the period

Putting values

==> A =

==> A= 2000

==> A =  2000(4.1776998×442409.523348)

==> A= 2000×1848254.17721

==> A= 3696508354.42 $

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3

step-by-step explanation:

a child is 12 years old, and his father is 32 years older. in how many years will the age of the father be 2 times the age of the child?

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this needs to be the answer format, or else your answer is incomplete.

if the number of years is x, then the equation is

in __ years