A derangement of rooks. Eight mutually antagonistic rooks are placed randomly on a standard chessboard with all arrangements equally likely. Determine the probability that no rook can capture any other rook (that is to say, that each rook occupies a distinct row and column of the chessboard).

The solution is attached below:

Step-by-step explanation:

is there a question here?

step-by-step explanation:

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get