A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 went to center field, 10 went to left center field, and 1 went left field.
1) What is the probability that a randomly selected home run was hit to the right field?
2) What is the probability that a randomly selected home run was hit to left field?
3) Was it unusual for this player to hit a home run to left field? Explain.
A. No, because Upper P left parenthesis right-center field right parenthesis greater than 0.05.No because P(right center field)>0.05.
B. Yes, because of P(right center-right center field)less than<0.5.
C. No, because the probability of an unusual event is 0.
D. No, because this player hit 19 home runs to right center field.

1. 19/60 = 0.32

2. 1/60 =0.12

Step-by-step explanation:

Right field = 19

Right center field =18

Center field =12

Left center field = 10

Left field = 1

Total home runs = 60

Let P stand for Probability

Then

1. P(right field) = 19/60 =0.32

2. P(left field) = 1/60 =0.12

3. Option C is the answer because the probability of an unusual events is less than 0.05. so 0 is also less than 0.05

i would pic false cause it goes down towards negative

step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .