Prove the divisibility of the following numbers: 45^10·5^40 by 25^20

For this case we have the following expressions:

and

Let:

(Integer m)

(Integer n)

By definition, an integer m is divisible by an integer n if the remainder of the division is 0. That is, there is an integer p such that:

Rewriting the expression we have:

So:

We cancel similar terms:

We check:

If they are divisible

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

the correct answer to your question is a. 4^4

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