A motorist encounters four consecutive traffic lights, each equally likely to be red or green. Let be the number of green lights passed by the motorist before being stopped by a red light. What is the probability distribution of E?

P (X = 0) = 0.50          P (X = 3) = 0.0625

P (X = 1) = 0.25           P (X = 4) = 0.0625

P (X = 2) = 0.125

Step-by-step explanation:

The random variable E is denoted as the number of green lights passed by the motorist before being stopped by a red light.

Then the random variable E can take values, E = {0, 1, 2, 3, 4}

The probability distribution table for the random variable E attached below.

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.