A manufacturer ships toasters in cartons of 10. In each carton, they estimate a 20% chance that any one of the toasters will need to be sent back for minor repairs. What is the probability that in a carton, there will be exactly 2 toasters that need repair? The probability of exactly 2 toasters needing repair is 0 0067 (Round to four decimal places as needed)

0.3019

Step-by-step explanation:

Let the total number of toasters in a carton (n) = 10

It is also said that there is a possibility that one of the toaster will be sent back  for repair is 20%

∴ if p = 0.2 and p + q = 1

It means that q = 1 -p

q = 1 - 0.2

q = 0.8

If we represent the A to be the number of coaster that need repair, The probability that exactly 2 coasters will need repair is required to be calculated.

Also, Let b = 2

From the foregoing, a binomial model is best fit to solve this problem.

Given that n= 10 and p = 0.20

To find P(A = 2); we have :

P(A = 2) =

 P(A = 2) =

P(A = 2) =

P(A = 2) =

P(A = 2) =

P(A = 2) =

P(A = 2) = 45 × (0.04) × (0.1677)

P(A = 2) = 0.30186

P(A = 2) = 0.3019  (to four decimal places)

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.