A building is known to be 192 feet tall. A ball is dropped from the top of the building. In how many seconds will the ball hit the ground if the formula for the height of the ball at t seconds is given by h=192−16t2? Step 1 of 2 : First, what is the height of the ball when it hits the ground?

Step-by-step explanation:

The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.

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Using that in the equation, we can solve for t.

  0 = 192 -16t^2

  0 = 12 -t^2 . . . . . . divide by 16

  t^2 = 12 . . . . . . . . add t^2

  t = √12 = 2√3 ≈ 3.464 . . . . take the square root

It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!