A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Btu/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours

$720

Step-by-step explanation:

Coefficient of performance of a refrigerator (COP) =

desired out i.e energy removed = 600Bth/hr

Required input=?

2.4=

required input==25Btu/hr

cost of electricity per hour = $0.08

cost of electricity for 360 hours =$0.08×360=$28.8

for an input of 25Btu/hr and 360 hours

∴cost of electricity in month =$28.8×25=$720

ege

step-by-step explanation:

egge

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer