When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has a student-t statistic of –2.50?

P-value = 0.009997                                                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 24

Nature of test: One-tailed test(Left tailed test)

We have to calculate the p-value.

Degree of freedom = n - 1 = 23

We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.

P-value = 0.009997

0.009997 is the  probability of a value being to the left of a number that has a student-t statistic of –2.50.

all it means is function 3

answer: approximately 206 bones

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