If the average (arithmetic mean) of 3a and 4b is less than 50, and a is twice b, what is the largest integer value of a?

The largest value of 'a' is less than 20

Step-by-step explanation:

If arithmetic mean of 3a and 4b is less than 50 i.e 3a+4b/2 < 50

3a+4b < 100... (1)

If a is twice as b, a = 2b... (2)

Substituting equation 2 into 1 we have, 3(2b)+4b < 100

6b+4b < 100

10b < 100

b < 10

Since a = 2b, a = 2×10 = 20

Therefore the largest value of 'a' is less than 20 which can be 19.9

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier