It was demonstrated in Example 2.5 from the textbook that shifting a binary number one bit to the left is equivalent to multiplying the number by 2. What operation is performed when a binary number is shifted one bit to the right

Evaluation of the integral part of the quotient of division by 2

Step-by-step explanation:

If shifting left by 1 bit is equivalent to multiplying by 2, it may seem intuitive to assume shifting right by 1 is equivalent to division by 2.

Consider the binary representation of 6: 110

Shifting right removes the last binary digit, so we have 11 which is binary of 3, indeed a division by 2.

Now, consider 101. This is 5 in binary. Shifting right by 1 bit removes the last 1, leaving 10, which is binary of 2. But we know 5÷2 = 2.5, not 2. What has happened is that the binary digits are integer representations. The fractional part has been truncated because it cannot be represented as an integer. This is why the shift operations work very well with integers.

Shifting right by 1 bit, then, truncates the fractional part of the result of division by 2, leaving the integral part.

i think it is 18

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.