A farmer has 2400 feet of fencing and wants to fence off a rectangular field that borders a straight river. Find the dimensions of the fence to maximize the area enclosed by the fence.

w- 600ft, L-1200ft

Step-by-step explanation:

Area = width*length

A(x) = x(2400-2x)

A(x) = 2400x - 2x^2

You have a quadratic with a = -2 and b = 2400

Maximum Area occurs where x = -b/2a = -2400/(2*-2) = 600 ft. (width)

length = 2400-2x = 2400-2*600 = 1200 (length)

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

only 10/60 isn't equivalent

hope this : )