A 40% dye solution is to mixed with a 53% dye solution to get 260L of a 50% solution. How many liters of the 40% and 50% solutions will be needed

From given,

Final solution is 260 liter

Let x be the liters of 40 % dye solution

Then, (260 - x) is the liters of 53 % dye solution

Therefore, according to question,

x liters of 40 % dye solution is mixed with (260 - x) liters of 53 % dye solution to get 260 liters of 50 % dye solution

40 % of x + 53 % of (260 - x) = 50 % of 260

Solve for "x"

Thus 60 liters of 40 % dye solution is used

Then, (260 - x) = 260 - 60 = 200

Thus 200 liters of 53 % dye solution is used

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: