Parallelogram F"G"H"J" is the final image after the rule
was applied to parallelogram FGHJ.

Parallelogram F double-prime G double-prime H double-prime J double-prime has points (3, 4), (2, 2), (4, 2), (5, 4).
What are the coordinates of vertex F of parallelogram FGHJ?

(–2, 2)
(–2, 6)
(–3, 4)
(–4, 2)

answer: idk wbu

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.