Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR = 8. Find XY^2.

We can drop a perpendicular from X to PQ at A, and from Y to RS at B.  Then XA = YB = 48/10 = 24/5. We can also draw a line through X parallel to BY meeting the line through Y parallel to RS at C.

Then XC = 24/5 + 24/5 +  10 = 98/5 and YC = 10 - 34/5 = 16/5, so XY^2 = XC^2 + YC^2 = (98/5)^2 + (16/5)^2 = 1972/5.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this