(A person bought a water
tank of circular base having the radius 10.5 m and height
21 m for the use of his community from the 'Gyani Tank
Factory'. If the upper part of the tank is semi spherical,
how many litre of water will be contained in the tank?)

About

Step-by-step explanation:

we know that

The volume of the tank is equal to the volume of a cylinder plus the volume of hemisphere

so

where

substitute

Convert to liters

therefore

The volume is equal to

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)