Point B is at (3,1).
For which segment is B a midpoint?
O AC with endpoints at A(1,-1) and C(5,3)
O AD with endpoints at A(1,-1) and C(6,4)
O AC with endpoints at A(1,-1) and C(8,6)
AC with endpoints at A(1, -1) and C(7,5)

AC with end points A (1,-1) and C (5,3)

Step-by-step explanation:

mid point is calculated using the equation

so from AC, with end points A (1,-1) and C (5,3). If we substitute the values back into the equation.

When we solve we get the same values for the midpoint

sorry I couldn't get Commas so I used dots

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.