What is the intersection point of Y equals X^2-2x+8 and y=x+6

Step-by-step explanation:

y = x^2-2x+8

y=x+6

x+6 = x^2 - 2x + 8

0 = x^2 - 2x + 8 - x - 6

0 = x^2 - 3x + 2

X1 = 2

X2 = 1

y1 = x + 6

y1 = 2 + 6

y1 = 8

y2 = x + 6

y2 = 1 + 6

y2 = 7

The lines have two intersection points: (2;8) and (1;7).

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: