Suppose we have a set of paired data, and let d = xafter − xbefore . The null hypothesis is H0 : μd = 0, the alternative hypothesis is Ha : μd ≠ 0, and the population standard deviation σ is not known. Jordan collects a sample of size n = 9 and computes d¯= 2.2 and sd = 3.3A) What is the value of the test statistic?B) The probability of obtaining a test statistic greater than Jordan's test statistic is 0.0403. Use this probability to determine the P-value for Jordan's hypothesis test. (Round to three decimal places.)

Using the paired t - test statistic, the value of the test statistic in the scenario above is 2 with a p-value of 0.081

Using the test statistic relation for a paired sample :

Plugging the values into the test statistic equation :

Hence, the test statistic = 2

Probability of obtaining a test statistic value greater than 2 = 0.0403

Since, it is a 2 - tailed test ;

P(t > 2) = 0.0408 × 2 = 0.0806 = 0.081 (3 decimal places).

Therefore, the p value for the hypothesis is 0.081.

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(a) The value of the test statistic is, t = 2.

(b) The p-value of the test is 0.081.

Step-by-step explanation:

The hypothesis for the paired difference test is:

H₀: vs. Hₐ:

Given:

(a)

The test statistic is:

The value of the test statistic is, t = 2.

(b)

It is provided that the .

But the hypothesis test is two-tailed.

The p-value for the two-tailed test is:

or

The p-value is:

Thus, the p-value of the test is 0.081.

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

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570, the answer is 570, hope it