In order to conduct an experiment, 55 subjects are randomly selected from a group of 4343 subjects. How many different groups of 55 subjects are possible?

962,598 different groups of 5 subjects are possible.

Step-by-step explanation:

The order is not important.

For example, Math, English, Business, Geography and History is the same group as English, Math, Business, Geography and History.

So we use the combinations formula to solve this problem.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

Combinations of 5 subjects from a set of 43

962,598 different groups of 5 subjects are possible.

mr. graef told us it is 13 pints

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.