Two students stting in adjacent seats in a lecture room have weights of 569 N and 673 N. Assume that Newton's law of universal gravitation can be applied to these two students and find the gravitational force (in Newtons) that one student exerts on the other when they are separated by 0.628 m.

6.73 x 10^-7 N.

Step-by-step explanation:

F1 = M1 * a

M1 = 569/9.81

= 58 kg

F2 = M2 * a

M2 = 673/9?81

= 68.6 kg

r = 0.628 m

Using force of attraction, F = (GM1M2)/r^2

Where,

G = 6.67408 × 10-11 m3/kg.s

F = (6.67408 × 10-11 * 68.6 * 58)/(0.628)^2

= 6.73 x 10^-7 N.

nlgqer

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