The pulse rate (in bpm) of a random sample of 30 Peruvian Indians was collected. The mean pulse rate of the sample is 70.2, with a sample standard deviation of 10.51. Compute a 95% confidence interval for the population mean. Assume the pulse rate is normally distributed

The 95% confidence interval for the population mean is between 66.44 bpm and 73.96 bpm.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 70.2 - 3.76 = 66.44 bpm

The upper end of the interval is the mean added to M. So it is 70.2 + 3.76 = 73.96 bpm

The 95% confidence interval for the population mean is between 66.44 bpm and 73.96 bpm.

hi there!

the answer will be d: 2

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: