You collect a random sample of size n from a population and calculate a 90% confidence interval. Which of the following strategies would produce a new confidence interval with an increased margin of error? Use an 80% confidence level. Use the same confidence level, but compute the interval n times. Approximately 10% of these intervals will be larger. Use an 85% confidence level. Decrease the sample size. Nothing can guarantee that you will obtain a larger margin of error. You can only say that the chance of obtaining a larger interval is 0.10.

Decrease the sample size.

Step-by-step explanation:

Margin of error is:

ME = CV × √(σ / n)

where σ is the population standard deviation, or:

ME = CV × √(p (1 − p) / n)

where p is the proportion.

In each case, the margin of error is directly proportional to the critical value, and inversely proportional to √n.

Lowering the confidence level will lower the critical value, which will decrease the margin of error.  Decreasing the sample size will increase the margin of error.

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation:

move it to the other side

step-by-step explanation: