For a party, three solid cheese balls with diameters of 2 inches, 4 inches, and 6 inches, respectively, were combined to form a single cheese ball. What was the approximate diameter, in inches, of the new cheese ball? (The volume of a sphere is 4 3 π r 3 , where r is the radius.)

The radius of the new cheese ball formed is approximately 6.603 inches.

Step-by-step explanation:

We are given the following in the question:

Radius of three cheese ball = 2 inches, 4 inches, and 6 inches

They were combined to form a new cheese ball.

Thus, we can write

Volume of three cheese balls =  Volume of new cheese ball.

Let r be the radius of new cheese ball.

Volume of sphere =

Putting values, we get:

Thus, the radius of the new cheese ball formed is approximately 6.603 inches.

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.