The diameter of small Nerf balls manufactured overseas is expected to be approximately normally distributed with a mean of 5.2 inches and a standard deviation of .08 inches. Suppose a random sample of 20 balls is selected. Calculate the mean of the sampling distribution of the sample mean.

5.2 inches

Step-by-step explanation:

The diameter of small Nerf balls follows normally distribution with mean 5.2 inches and standard deviation 0.08 inches.

We have to calculate the mean of sampling distribution when 20 balls are selected randomly.

Here, μ=5.2 and σ=0.08.

We know that mean of sampling distribution for mean is equal to the population mean.

mean of sampling distribution for mean= μxbar=μ= 5.2

Thus, mean of the sampling distribution of the sample mean is 5.2 inches

she will most likely have 33  

step-by-step explanation:

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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