A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square? A square with a side length of 4 units is shown. A diagonal is drawn with one section shaded inside the figure. fraction 1 over 2 ⋅ 4 ⋅ 4 fraction 1 over 4 ⋅ 4 ⋅ 4 fraction 1 over 2 ⋅ 2 ⋅ 2 fraction 1 over 4 ⋅ 2 ⋅ 2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: apothems is your answer

step-by-step explanation: hope u get it right

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