How is the graph of the parent quadratic function transformed to produce the graph of y = negative (2 x + 6) squared + 3?

We start with the parent function

The first child function would be

We have multiplied the input of the function by a constant: we have

This kind of transformation result in a horizontal stretch/compression. If the multiplier is greater than 1, we have a compression. So, this first child causes a horizontal compression with compression rate 2.

The second child function would be

We added 6 to  the input of the function: we have

This kind of transformation result in a horizontal translation. If the constant added is positive, we translate to the left. So, this second child causes a translation 6 units to the left.

The third child function would be

We changed the sign of the previous function (i.e. we multiplied it by -1): we have

This kind of transformation result in a vertical stretch/compression. If the multiplier is greater than 1 we have a stretch, if it's between 0 and 1 we have compression. If it's negative, we reflect across the x axis, and then apply the stretch/compression. In this case, the multiplier is -1, so we only reflect across the x axis.

The fourth child function would be

We added 3 to previous function: we have

This kind of transformation result in a vertical translation. If the constant added is positive, we translate upwards. So, this last child causes a translation 3 units up.

Recap

Starting from the parent function , we have to:

Note that the order is important!

B

Step-by-step explanation:

i know the other answer was a little confusing, but they did more, so feel free to give them brainliest, just wanted to help clarify :)

edgenuity 2020

only 10/60 isn't equivalent

hope this : )