Madison has a choice of two entrees (soup or salad), three main courses (fish, chicken or steak) and three desserts (ice-cream, lemon tart or cheese).

Suppose Madison has the choice to omit the entree and/or the dessert course altogether.

Find the probability that:
she chooses soup, fish and lemon tart

she chooses all three courses

she chooses only two courses

she has only the main course.

Find the probability that:

she chooses soup, fish and lemon tart

Soup would be 1/2

Fish would be 1/3

Lemon tart would be 1/3

Picking all 3: 1/2 x 1/3 x 1/3 = 1/18

she chooses all three courses

Total food choices = 2 + 3 +3 = 8

Picking entree = 2/8 = 1/4

Picking main course = 3/7

Picking desert = 3/6 = 1/2

Total probability: 1/4 x 3/7 x 1/2 = 3/56

Picking just the main course = 3/8

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.