A baker blends 600 raisins and 400 chocolate chips into a dough mix and, from this, makes 500 cookies. (a) Find the probability that a randomly picked cookie will have no raisins. (b) Find the probability that a randomly picked cookie will have exactly two chocolate chips. (c) Find the probability that a randomly chosen cookie will have at least two bits (raisins or chips) in it.

a) P(X = 0) for raisins = 0.33287

b) P(X = 2) for chocolate chips = 0.14379

c) P(X ≥ 2) for both bits = 0.59399

Step-by-step explanation:

The average amount of raisin per cookie is 600/500 = 1.2

The average amount of chocolate chips per cookie = 400/500 = 0.8

a) Using Poisson's distribution function

P(X = x) = (e^-λ)(λˣ)/x!

For raisin, Mean = λ = 1.1

x = 0

P(X = 0) = (e⁻¹•¹)(1.1⁰)/(0!) = 0.33287

b) Using Poisson's distribution function

P(X = x) = (e^-λ)(λˣ)/x!

For chocolate chips, Mean = λ = 0.8

x = 2

P(X = 2) = (e⁻⁰•⁸)(0.8²)/(2!) = 0.14379

c) the probability that a randomly chosen cookie will have at least two bits (raisins or chips) in it.

For this, the average number of bit in a raisin = (600+400)/500 = 2 bits per raisin.

P(X ≥ 2) = 1 - [P(X = 0) + P(X = 1)]

For P(X = 0)

P(X = x) = (e^-λ)(λˣ)/x!

Mean = λ = 2

x = 0

P(X = 0) = (e⁻²)(2⁰)/(0!) = 0.13534

For P(X = 1)

P(X = x) = (e^-λ)(λˣ)/x!

Mean = λ = 2

x = 1

P(X = 1) = (e⁻²)(2¹)/(1!) = 0.27067

P(X ≥ 2) = 1 - [P(X = 0) + P(X = 1)]

P(X ≥ 2) = 1 - (0.13534 + 0.27067) = 1 - 0.40601 = 0.59399

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.