Quincy is going on a vacation to Australia. His flight leaves at 9:50 A. M. It takes 20 minutes to get to the airport, and Quincy wants to be at the airport 1 hour and 5 minutes before his flight leaves. What is the latest time that Quincy can leave for the airport?

If it takes 20 minute to get to the airport, and he wants to be there an hour and 5 minutes before his flight leaves, we have to subtract the time he leaves (9:50) by 1 hour and 5.

9:50 - 1 hour and 5 minutes.

9:50 - 65 minutes.

9:50 - 65 = 8:45.

Which means he must be at the airport at 8:45.

BUT,

The question is asking for the latest time that Quincy can LEAVE for the airport, which means it's 8:45 - 20 minutes, since it takes 20 minutes to get to the airport:

8:45 - 20 = 8:25

the latest time is 8:25 AM

Step-by-step explanation:

It takes 20 minutes to get to the airport. If Quincy wants to be at the airport 1 hour and 5 minutes before his flight leaves, it means that the maximum amount of time that Quincy has before left before she gets to the airport is

1 hour + (20 + 5) minutes = 1 hour 25 minutes.

His flight leaves at 9:50 A.M. This means that the latest time that Quincy can leave for the airport would be 9:50 A.M. - 1:25

= 8:25 AM

the answer to the question is a  

it has the same slope and the same y-intercept.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.