A solid figure is
separated into two rectangular prisms.
The volume of Rectangular Prism A is
80 cubic feet. Rectangular Prism B has
a length of 6 feet and a width of 5 feet.
The total volume of the solid figure is
200 cubic feet. What is the height of
Rectangular Prism B? Show your work
and explain your answer.
Thank you!

4 feet.

Step-by-step explanation:

Their is one rectangular prison divided into two.

The volume of the first one is

V1= L X H X W=80.

Volume of the second one is

V2= L X H X W

V2= 6 X H X 5

V2 = 30H

Now from the question, the total volume is 200cubic feet which means V1 + V2 = 200, recall that V1=80 and V2=30H, so we say;

80+30H=200, collecting the like term we have, 30H=200-80.

30H=120, divide both side by 30

30H/30=120/30

H= 4feet.

Height is 4feet.

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d