Which plane is closer to the base of the airplane tower? explain. The distance for Plane A, to the nearest tenth, is _ kilometers. The distance for Plane B, to the nearest tenth, is _ kilometers. help!!

Plane B is closer.

The distance for Plane A is 7.9 km.

The distance for Plane B is 7.4 km.

Step-by-step explanation:

To find the distance to the tower, altitude must be converted to kilometers. Each 1000 ft is 0.3048 km, so the heights of the planes are ...

-- Plane A: (20 thousand ft)*(0.3048 km/thousand ft) = 6.096 km

-- Plane B: (8 thousand ft)*(0.3048 km/thousand ft) = 2.4384 km

The Pythagorean theorem can be used to find the distance from each plane to the tower:

-- distance = √((ground distance)² + (height)²)

-- Plane A distance = √(5² +6.096²) ≈ √62.16 ≈ 7.9 . . . km

-- Plane B distance = √(7² +2.4384²) ≈ √54.95 ≈ 7.4 . . . km

The distance for Plane B is shorter, so Plane B is closer to the tower.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

answer: get jesus in your life

step-by-step explanation: