Find an equation of the line that satisfies the given conditions: through (1/2, − 2/3); perpendicular to the line 6x − 12y = 1

First make the equation to slope intercept
y=1/2-1/12
the slope of the perpendicular is equal to the negative inverse
m=-2
now substitute known variable in slope intercept form
-2/3=-2(1/2)+b
-2/3=-1+b
b=1/3
y=-2x+1/3
in standard
6x+3y=1