A triangle has vertices at B(-3,0), C(2, -1), D(-1,2). Which series of transformations would produce an image with vertices B"(4,1), C"(-1,0), D"(2, 3)?
(x, y) - (x,-y), (x, y) - (x + 1, y + 1)
(x, y) -- (-x, y),(x, y) - (x + 1, y + 1)
(x, y) -- (X. -y). (x, y) - (x + 2 y + 2)
(X, Y)-(-x, y),(, y) - (x + 2 y + 2)

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

dont think so

step-by-step explanation:

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )